How fast does a 95 mph baseball travel from the mound to home plate in seconds?
Question:I figured .43 seconds. Please show work
Answers:
Twins losing three important people before opening season the last three years, how rough is that?
Since when does a pitcher release the ball 60'6" from home plate, the rubber may be 60'6" from home but a pitcher does not release the baseball that distance from home plate.The actual time is approximately .375 seconds from release to home.
"Show your work" >Too many variables, height of pitcher, length of arm, length of pitchers stride, etc<
"The Physics of Baseball" Dr. Robert K. Adair
95 x 1.47 = 139.65 feet per second divided by 60'6" = .4347826seconds...you were right on...nice work...
In baseball, when can you tag up on a fly ball? (When the ball is touched or when it is caught)?
Why is it multiplied by 1.47?Thanks
Would't it be nice to get rid of the DH alltogether ?
1 mile = 5280 ft1 hour = 3600 sec
1 mph = 1.47 ft/sec
95 mph x 1.47 = 139.33
60.5 ft
----------------- = 0.4342 sec
139.33 ft/sec
The first responder is correct and the poster are correct - it would take approx 0.43 seconds for a 95 mph fastball to reach the plate. I just wanted to clarify why the mph is multiplied by 1.47.
Which player, other than Albert Pujols, has a good shot at winning a Triple Crown in the future?
Actually, you need to account for the size of the baseball, and it's weight in motion, not at rest.So the equation is:
95 x 1.87 = 177.65 feet per second divided by 60'6" = 1.936 seconds.
Do you want nbc to have the game of the week again with bob costas?
1 mile = 5280 feet1 hour = 3600 seconds
5280 / 3600 = 1.4666666 feet per second
95 x 1.4666666 = 139.33332 feet per second
60.5 / 139.33332 = .4342105 seconds for a 95 mph fastball to travel from the mound to home plate.
More Questions & Answers...