If there is man on 1 st and 2nd and its droped thired strike can they throw to 3rd and 2nd as forces?


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you can't run on a dropped third strike if 1st base is occupied. That options off the table so the answer to your question is no. BUT if the runner's on 2nd and third decide to go then they can make the play but not as forces. they'd have to tag as if they were being stolen.

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they could only if the person on first decides to move...becuase it is a big gamble so sure if you want to but if the person on first isnt moving then dont risk it

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Both answers above me are wrong. Batter is out because first is occupied. Runners at second and first and advance at thier own risk. But there would be no force out they would have to be tagged out just like a steal. That is the right answer.

What will happen?

The previous answers are only partially correct. If there are no outs or 1 out and first base is occupied, the dropped third strike doesn't matter; the batter is still out. However, if there are 2 outs, the batter may advance and any resulting force out is in play.

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If there are 0 or 1 outs, the batter is out. If there are 2 outs, there is a force at first, second, or third base.

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Only if there are aleady 2 out in the inning. With less than 2 outs, and runners on first and second, or first, second and third, the batter cannot attempt to take 1st on a dropped third strike. That's why the rule is in place.

It's 6.05(c) of the rulebook.

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If the runners hold, no. If they take off then its treated like a steal attempt. If no one's on first and the 3rd strike is dropped and not foul tipped then the batter can try to get to first.

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No, the batter can only advance on a dropped third strike if first base is open. It the ball gets away and the runners try to advance they can be thrown out, but it doesn't become a force because the hitter is out. If there are two outs in the inning however the hitting isn't out creating a force at all three bases.

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if a runner is on first and there is a drop third strike the batter is automatically out and the runners advance at there on will so if the runner on first runs to second then he can throw to third

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Only if there were two outs before the third strike. I wouldn't advise such a throw to either base, considering that the runners on first and second would have taken leads.

If there were less than two outs before the third strike, then the batter is out anyway. This is so the catcher can't drop the ball intentionally to turn a double play.

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If 0 or 1 out it would be treated as any other steal play, so no force play in effect. Batter out because first base is occupied at the time of the pitch.

With 2 outs the runners could be forced out because the batter is not out on a dropped third strike with 2 outs.

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