How do you calculate ERA in base?ball?

Question:

Answers:

Earned runs allowed x nine, divided by innings pitched.
Example: 4 ER x 9 = 36 divided by 9 innings = 4.00 ERA
Say a pitcher allows 4 earned runs in only 7 innings. That would be: 4 x 9 = 36 / 7 = 5.14 ERA
Now let's say a pitcher has a fraction of an inning, 1/3 or 2/3.
Example: 4 x 9 = 36 / 6 2/3. Here's where you multiply two numbers by 3. (36) becomes 108, and 6 2/3 becomes 20, (because that's how many out he got). So 108 / 20 becomes 5.40.
There's one more. The first game of the year and the starting pitcher gives up 4 earned runs in the first inning and gets only one batter out. Now you multiply two numbers by 3.
Example: 4 x 9 = 36 / 1/3 becomes - 36 x 3 = 108 / 1 = 108.00 ERA.
Say he gets two outs: 4 x 9 = 36 / 2/3 becomes - 36 x 3 = 108 / 2 = 54.00 ERA.
Okay, one step further. He gets no outs. This one is outta sight, but only lasts until he gets a few batters out.
4 x 9 = 36 / 0 becomes 36 x 27 (because that's how many outs in a regulation game) = 927.00 ERA.
Two last examples to show how 1/3 of an inning will change a pitcher's ERA.
32 earned runs in 77 innings: 32 x 9 = 288 / 77 = 3.74.
32 x 9 = 288 x 3 = 864 / (77 1/3 x 3) 232 = 3.72.
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Mutiply the runs scored by 9 then divide by the innings pitched

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Earned Runs x 9 / Innings Pitched

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